Base | Representation |
---|---|
bin | 111100010010010101010111… |
… | …0110000101110101100100100 |
3 | 2120112120210012210022121212011 |
4 | 1320210222232300232230210 |
5 | 1024001143411212141300 |
6 | 5115453422213404004 |
7 | 216460565445133555 |
oct | 17044525660565444 |
9 | 2515523183277764 |
10 | 530285364177700 |
11 | 143a6883a62720a |
12 | 4b584a33639604 |
13 | 199b7906693c51 |
14 | 94d3d3cc4232c |
15 | 4148e1500aeba |
hex | 1e24aaec2eb24 |
530285364177700 has 18 divisors (see below), whose sum is σ = 1150719240265826. Its totient is φ = 212114145671040.
The previous prime is 530285364177697. The next prime is 530285364177731. The reversal of 530285364177700 is 7771463582035.
It can be written as a sum of positive squares in 3 ways, for example, as 1247827511844 + 529037536665856 = 1117062^2 + 23000816^2 .
It is a super-2 number, since 2×5302853641777002 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2651426820789 + ... + 2651426820988.
Almost surely, 2530285364177700 is an apocalyptic number.
530285364177700 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
530285364177700 is an abundant number, since it is smaller than the sum of its proper divisors (620433876088126).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530285364177700 is a wasteful number, since it uses less digits than its factorization.
530285364177700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5302853641791 (or 5302853641784 counting only the distinct ones).
The product of its (nonzero) digits is 29635200, while the sum is 58.
The spelling of 530285364177700 in words is "five hundred thirty trillion, two hundred eighty-five billion, three hundred sixty-four million, one hundred seventy-seven thousand, seven hundred".
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