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5303000044313 is a prime number
BaseRepresentation
bin100110100101011001101…
…1011110001001100011001
3200202221222012011012021122
41031022303123301030121
51143341021002404223
615140055315015025
71055062166433416
oct115126333611431
920687865135248
105303000044313
111764a98304524
1271790bb9a475
132c60bc5c160a
1414494910310d
1592e234825c8
hex4d2b36f1319

5303000044313 has 2 divisors, whose sum is σ = 5303000044314. Its totient is φ = 5303000044312.

The previous prime is 5303000044283. The next prime is 5303000044333. The reversal of 5303000044313 is 3134400003035.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3762502040089 + 1540498004224 = 1939717^2 + 1241168^2 .

It is a cyclic number.

It is not a de Polignac number, because 5303000044313 - 214 = 5303000027929 is a prime.

It is not a weakly prime, because it can be changed into another prime (5303000044333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651500022156 + 2651500022157.

It is an arithmetic number, because the mean of its divisors is an integer number (2651500022157).

Almost surely, 25303000044313 is an apocalyptic number.

It is an amenable number.

5303000044313 is a deficient number, since it is larger than the sum of its proper divisors (1).

5303000044313 is an equidigital number, since it uses as much as digits as its factorization.

5303000044313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 26.

Adding to 5303000044313 its reverse (3134400003035), we get a palindrome (8437400047348).

The spelling of 5303000044313 in words is "five trillion, three hundred three billion, forty-four thousand, three hundred thirteen".