Base | Representation |
---|---|
bin | 100110100101011001101… |
… | …1011110001001100011001 |
3 | 200202221222012011012021122 |
4 | 1031022303123301030121 |
5 | 1143341021002404223 |
6 | 15140055315015025 |
7 | 1055062166433416 |
oct | 115126333611431 |
9 | 20687865135248 |
10 | 5303000044313 |
11 | 1764a98304524 |
12 | 71790bb9a475 |
13 | 2c60bc5c160a |
14 | 14494910310d |
15 | 92e234825c8 |
hex | 4d2b36f1319 |
5303000044313 has 2 divisors, whose sum is σ = 5303000044314. Its totient is φ = 5303000044312.
The previous prime is 5303000044283. The next prime is 5303000044333. The reversal of 5303000044313 is 3134400003035.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3762502040089 + 1540498004224 = 1939717^2 + 1241168^2 .
It is a cyclic number.
It is not a de Polignac number, because 5303000044313 - 214 = 5303000027929 is a prime.
It is not a weakly prime, because it can be changed into another prime (5303000044333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651500022156 + 2651500022157.
It is an arithmetic number, because the mean of its divisors is an integer number (2651500022157).
Almost surely, 25303000044313 is an apocalyptic number.
It is an amenable number.
5303000044313 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303000044313 is an equidigital number, since it uses as much as digits as its factorization.
5303000044313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 26.
Adding to 5303000044313 its reverse (3134400003035), we get a palindrome (8437400047348).
The spelling of 5303000044313 in words is "five trillion, three hundred three billion, forty-four thousand, three hundred thirteen".
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