Base | Representation |
---|---|
bin | 1111011011110001010… |
… | …01111111111010001000 |
3 | 1212200210212220002000022 |
4 | 13231320221333322020 |
5 | 32142031121044000 |
6 | 1043341402000012 |
7 | 53212313163545 |
oct | 7557051777210 |
9 | 1780725802008 |
10 | 530305253000 |
11 | 1949a0543636 |
12 | 8693a1a6008 |
13 | 3b01382c943 |
14 | 1b94a00bbcc |
15 | dbdb457585 |
hex | 7b78a7fe88 |
530305253000 has 32 divisors (see below), whose sum is σ = 1240914294360. Its totient is φ = 212122100800.
The previous prime is 530305252933. The next prime is 530305253011. The reversal of 530305253000 is 352503035.
It can be written as a sum of positive squares in 4 ways, for example, as 44220201796 + 486085051204 = 210286^2 + 697198^2 .
It is a super-2 number, since 2×5303052530002 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 265151627 + ... + 265153626.
Almost surely, 2530305253000 is an apocalyptic number.
530305253000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
530305253000 is an abundant number, since it is smaller than the sum of its proper divisors (710609041360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530305253000 is a wasteful number, since it uses less digits than its factorization.
530305253000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 530305274 (or 530305260 counting only the distinct ones).
The product of its (nonzero) digits is 6750, while the sum is 26.
Adding to 530305253000 its reverse (352503035), we get a palindrome (530657756035).
The spelling of 530305253000 in words is "five hundred thirty billion, three hundred five million, two hundred fifty-three thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •