Base | Representation |
---|---|
bin | 111100010010101110111111… |
… | …1110100100100110001101100 |
3 | 2120112210001022010001200111121 |
4 | 1320211131333310210301230 |
5 | 1024003044130233400330 |
6 | 5115535004351030324 |
7 | 216464554533310453 |
oct | 17045357764446154 |
9 | 2515701263050447 |
10 | 530340411231340 |
11 | 143a8a118215376 |
12 | 4b59363680b3a4 |
13 | 199bcb69c58838 |
14 | 94d68819a1b9a |
15 | 414a5879ee17a |
hex | 1e2577fd24c6c |
530340411231340 has 24 divisors (see below), whose sum is σ = 1115197839467712. Its totient is φ = 211853692896000.
The previous prime is 530340411231299. The next prime is 530340411231361. The reversal of 530340411231340 is 43132114043035.
It is a junction number, because it is equal to n+sod(n) for n = 530340411231296 and 530340411231305.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17654459389 + ... + 17654489428.
It is an arithmetic number, because the mean of its divisors is an integer number (46466576644488).
Almost surely, 2530340411231340 is an apocalyptic number.
It is an amenable number.
530340411231340 is an abundant number, since it is smaller than the sum of its proper divisors (584857428236372).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530340411231340 is a wasteful number, since it uses less digits than its factorization.
530340411231340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35308949577 (or 35308949575 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 530340411231340 its reverse (43132114043035), we get a palindrome (573472525274375).
The spelling of 530340411231340 in words is "five hundred thirty trillion, three hundred forty billion, four hundred eleven million, two hundred thirty-one thousand, three hundred forty".
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