Base | Representation |
---|---|
bin | 100110100101100110100… |
… | …1100000011110111111111 |
3 | 200210000002022012122002200 |
4 | 1031023031030003313333 |
5 | 1143342412111243033 |
6 | 15140210232122543 |
7 | 1055105664226503 |
oct | 115131514036777 |
9 | 20700068178080 |
10 | 5303432134143 |
11 | 176519a1a7a60 |
12 | 717a10836453 |
13 | 2c615ac8a180 |
14 | 14498a65c303 |
15 | 92e4b384013 |
hex | 4d2cd303dff |
5303432134143 has 48 divisors (see below), whose sum is σ = 9054977253504. Its totient is φ = 2948752745280.
The previous prime is 5303432134141. The next prime is 5303432134201. The reversal of 5303432134143 is 3414312343035.
5303432134143 is a `hidden beast` number, since 5 + 303 + 4 + 3 + 2 + 1 + 341 + 4 + 3 = 666.
It is not a de Polignac number, because 5303432134143 - 21 = 5303432134141 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5303432134098 and 5303432134107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303432134141) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12430621 + ... + 12850182.
It is an arithmetic number, because the mean of its divisors is an integer number (188645359448).
Almost surely, 25303432134143 is an apocalyptic number.
5303432134143 is a deficient number, since it is larger than the sum of its proper divisors (3751545119361).
5303432134143 is a wasteful number, since it uses less digits than its factorization.
5303432134143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25280996 (or 25280993 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 36.
Adding to 5303432134143 its reverse (3414312343035), we get a palindrome (8717744477178).
The spelling of 5303432134143 in words is "five trillion, three hundred three billion, four hundred thirty-two million, one hundred thirty-four thousand, one hundred forty-three".
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