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5303432134141 is a prime number
BaseRepresentation
bin100110100101100110100…
…1100000011110111111101
3200210000002022012122002121
41031023031030003313331
51143342412111243031
615140210232122541
71055105664226501
oct115131514036775
920700068178077
105303432134141
11176519a1a7a59
12717a10836451
132c615ac8a17b
1414498a65c301
1592e4b384011
hex4d2cd303dfd

5303432134141 has 2 divisors, whose sum is σ = 5303432134142. Its totient is φ = 5303432134140.

The previous prime is 5303432134139. The next prime is 5303432134201. The reversal of 5303432134141 is 1414312343035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4146839431641 + 1156592702500 = 2036379^2 + 1075450^2 .

It is a cyclic number.

It is not a de Polignac number, because 5303432134141 - 21 = 5303432134139 is a prime.

Together with 5303432134139, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 5303432134097 and 5303432134106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5303432194141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651716067070 + 2651716067071.

It is an arithmetic number, because the mean of its divisors is an integer number (2651716067071).

Almost surely, 25303432134141 is an apocalyptic number.

It is an amenable number.

5303432134141 is a deficient number, since it is larger than the sum of its proper divisors (1).

5303432134141 is an equidigital number, since it uses as much as digits as its factorization.

5303432134141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 5303432134141 its reverse (1414312343035), we get a palindrome (6717744477176).

The spelling of 5303432134141 in words is "five trillion, three hundred three billion, four hundred thirty-two million, one hundred thirty-four thousand, one hundred forty-one".