Base | Representation |
---|---|
bin | 1111011011110111001… |
… | …00011011000101000101 |
3 | 1212200221021211221011011 |
4 | 13231323210123011011 |
5 | 32142131123414302 |
6 | 1043350305242221 |
7 | 53213445444112 |
oct | 7557344330505 |
9 | 1780837757134 |
10 | 530354123077 |
11 | 194a16092429 |
12 | 86952633371 |
13 | 3b0209b094c |
14 | 1b9526cd909 |
15 | dbe08ac5d7 |
hex | 7b7b91b145 |
530354123077 has 2 divisors, whose sum is σ = 530354123078. Its totient is φ = 530354123076.
The previous prime is 530354123041. The next prime is 530354123141. The reversal of 530354123077 is 770321453035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 524561238756 + 5792884321 = 724266^2 + 76111^2 .
It is a cyclic number.
It is not a de Polignac number, because 530354123077 - 215 = 530354090309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530354123977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265177061538 + 265177061539.
It is an arithmetic number, because the mean of its divisors is an integer number (265177061539).
Almost surely, 2530354123077 is an apocalyptic number.
It is an amenable number.
530354123077 is a deficient number, since it is larger than the sum of its proper divisors (1).
530354123077 is an equidigital number, since it uses as much as digits as its factorization.
530354123077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 264600, while the sum is 40.
The spelling of 530354123077 in words is "five hundred thirty billion, three hundred fifty-four million, one hundred twenty-three thousand, seventy-seven".
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