Base | Representation |
---|---|
bin | 1111011011110111001… |
… | …00011011000110000101 |
3 | 1212200221021211221020112 |
4 | 13231323210123012011 |
5 | 32142131123420031 |
6 | 1043350305242405 |
7 | 53213445444233 |
oct | 7557344330605 |
9 | 1780837757215 |
10 | 530354123141 |
11 | 194a16092487 |
12 | 86952633405 |
13 | 3b0209b099b |
14 | 1b9526cd953 |
15 | dbe08ac62b |
hex | 7b7b91b185 |
530354123141 has 2 divisors, whose sum is σ = 530354123142. Its totient is φ = 530354123140.
The previous prime is 530354123077. The next prime is 530354123161. The reversal of 530354123141 is 141321453035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 501375870241 + 28978252900 = 708079^2 + 170230^2 .
It is a cyclic number.
It is not a de Polignac number, because 530354123141 - 26 = 530354123077 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530354123098 and 530354123107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530354123161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265177061570 + 265177061571.
It is an arithmetic number, because the mean of its divisors is an integer number (265177061571).
Almost surely, 2530354123141 is an apocalyptic number.
It is an amenable number.
530354123141 is a deficient number, since it is larger than the sum of its proper divisors (1).
530354123141 is an equidigital number, since it uses as much as digits as its factorization.
530354123141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 530354123141 its reverse (141321453035), we get a palindrome (671675576176).
The spelling of 530354123141 in words is "five hundred thirty billion, three hundred fifty-four million, one hundred twenty-three thousand, one hundred forty-one".
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