Base | Representation |
---|---|
bin | 110001011001001101… |
… | …111011111011110111 |
3 | 12001220012101221211122 |
4 | 301121031323323313 |
5 | 1332104311330033 |
6 | 40210430454155 |
7 | 3555202146341 |
oct | 613115737367 |
9 | 161805357748 |
10 | 53036433143 |
11 | 20546758231 |
12 | a34196435b |
13 | 5002b6c425 |
14 | 27d1adc291 |
15 | 15a6233a98 |
hex | c5937bef7 |
53036433143 has 2 divisors, whose sum is σ = 53036433144. Its totient is φ = 53036433142.
The previous prime is 53036433137. The next prime is 53036433157. The reversal of 53036433143 is 34133463035.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53036433143 - 28 = 53036432887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53036433743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26518216571 + 26518216572.
It is an arithmetic number, because the mean of its divisors is an integer number (26518216572).
Almost surely, 253036433143 is an apocalyptic number.
53036433143 is a deficient number, since it is larger than the sum of its proper divisors (1).
53036433143 is an equidigital number, since it uses as much as digits as its factorization.
53036433143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 35.
Adding to 53036433143 its reverse (34133463035), we get a palindrome (87169896178).
The spelling of 53036433143 in words is "fifty-three billion, thirty-six million, four hundred thirty-three thousand, one hundred forty-three".
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