Base | Representation |
---|---|
bin | 1111011011111100100… |
… | …11110111000111101110 |
3 | 1212201001111101110122121 |
4 | 13231332103313013232 |
5 | 32142224412110014 |
6 | 1043355031103154 |
7 | 53214544400653 |
oct | 7557623670756 |
9 | 1781044343577 |
10 | 530400113134 |
11 | 194a3a044441 |
12 | 86965b11aba |
13 | 3b02a393ab8 |
14 | 1b958861c2a |
15 | dbe4944124 |
hex | 7b7e4f71ee |
530400113134 has 16 divisors (see below), whose sum is σ = 810506962800. Its totient is φ = 260246926144.
The previous prime is 530400113069. The next prime is 530400113167. The reversal of 530400113134 is 431311004035.
It is a junction number, because it is equal to n+sod(n) for n = 530400113099 and 530400113108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3882697 + ... + 4016980.
It is an arithmetic number, because the mean of its divisors is an integer number (50656685175).
Almost surely, 2530400113134 is an apocalyptic number.
530400113134 is a deficient number, since it is larger than the sum of its proper divisors (280106849666).
530400113134 is a wasteful number, since it uses less digits than its factorization.
530400113134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7900307.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 530400113134 its reverse (431311004035), we get a palindrome (961711117169).
It can be divided in two parts, 5304001 and 13134, that added together give a palindrome (5317135).
The spelling of 530400113134 in words is "five hundred thirty billion, four hundred million, one hundred thirteen thousand, one hundred thirty-four".
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