53040153503 has 2 divisors, whose sum is σ = 53040153504. Its totient is φ = 53040153502.

The previous prime is 53040153499. The next prime is 53040153511. The reversal of 53040153503 is 30535104035.

53040153503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53040153503 - 2² = 53040153499 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53040153533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26520076751 + 26520076752.

It is an arithmetic number, because the mean of its divisors is an integer number (26520076752).

Almost surely, 2^53040153503 is an apocalyptic number.

53040153503 is a deficient number, since it is larger than the sum of its proper divisors (1).

53040153503 is an equidigital number, since it uses as much as digits as its factorization.

53040153503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 29.

Adding to 53040153503 its reverse (30535104035), we get a palindrome (83575257538).

The spelling of 53040153503 in words is "fifty-three billion, forty million, one hundred fifty-three thousand, five hundred three".