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53040153533 is a prime number
BaseRepresentation
bin110001011001011100…
…001000001110111101
312001220110101222020212
4301121130020032331
51332111234403113
640211042322205
73555245603063
oct613134101675
9161813358225
1053040153533
1120548869434
12a343059365
135003872943
1427d23ca033
1515a671b0a8
hexc597083bd

53040153533 has 2 divisors, whose sum is σ = 53040153534. Its totient is φ = 53040153532.

The previous prime is 53040153511. The next prime is 53040153557. The reversal of 53040153533 is 33535104035.

53040153533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44756787364 + 8283366169 = 211558^2 + 91013^2 .

It is a cyclic number.

It is not a de Polignac number, because 53040153533 - 226 = 52973044669 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53040153533.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53040153503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26520076766 + 26520076767.

It is an arithmetic number, because the mean of its divisors is an integer number (26520076767).

Almost surely, 253040153533 is an apocalyptic number.

It is an amenable number.

53040153533 is a deficient number, since it is larger than the sum of its proper divisors (1).

53040153533 is an equidigital number, since it uses as much as digits as its factorization.

53040153533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40500, while the sum is 32.

Adding to 53040153533 its reverse (33535104035), we get a palindrome (86575257568).

The spelling of 53040153533 in words is "fifty-three billion, forty million, one hundred fifty-three thousand, five hundred thirty-three".