53050040541131 has 2 divisors, whose sum is σ = 53050040541132. Its totient is φ = 53050040541130.

The previous prime is 53050040541097. The next prime is 53050040541133. The reversal of 53050040541131 is 13114504005035.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53050040541131 is a prime.

It is a super-2 number, since 2×53050040541131² (a number of 28 digits) contains 22 as substring.

Together with 53050040541133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (53050040541133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26525020270565 + 26525020270566.

It is an arithmetic number, because the mean of its divisors is an integer number (26525020270566).

Almost surely, 2^{53050040541131} is an apocalyptic number.

53050040541131 is a deficient number, since it is larger than the sum of its proper divisors (1).

53050040541131 is an equidigital number, since it uses as much as digits as its factorization.

53050040541131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 53050040541131 its reverse (13114504005035), we get a palindrome (66164544546166).

The spelling of 53050040541131 in words is "fifty-three trillion, fifty billion, forty million, five hundred forty-one thousand, one hundred thirty-one".