Base | Representation |
---|---|
bin | 1001111000011010… |
… | …01011101111111101 |
3 | 111200201101210001221 |
4 | 10330031023233331 |
5 | 41331043300003 |
6 | 2234225433341 |
7 | 245315143210 |
oct | 47415135775 |
9 | 14621353057 |
10 | 5305056253 |
11 | 2282625312 |
12 | 104079b851 |
13 | 667109c53 |
14 | 3847cd777 |
15 | 210b137bd |
hex | 13c34bbfd |
5305056253 has 32 divisors (see below), whose sum is σ = 6519398400. Its totient is φ = 4215571776.
The previous prime is 5305056247. The next prime is 5305056259. The reversal of 5305056253 is 3526505035.
It is an interprime number because it is at equal distance from previous prime (5305056247) and next prime (5305056259).
It is a cyclic number.
It is not a de Polignac number, because 5305056253 - 25 = 5305056221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5305056259) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3685908 + ... + 3687346.
It is an arithmetic number, because the mean of its divisors is an integer number (203731200).
Almost surely, 25305056253 is an apocalyptic number.
5305056253 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
5305056253 is a deficient number, since it is larger than the sum of its proper divisors (1214342147).
5305056253 is a wasteful number, since it uses less digits than its factorization.
5305056253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2041.
The product of its (nonzero) digits is 67500, while the sum is 34.
The square root of 5305056253 is about 72835.8171025767. The cubic root of 5305056253 is about 1744.0676681171.
The spelling of 5305056253 in words is "five billion, three hundred five million, fifty-six thousand, two hundred fifty-three".
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