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53053005000049 is a prime number
BaseRepresentation
bin11000001000000010111011…
…00001000110110101110001
320221211211002010200112022221
430010001131201012311301
523423210023240000144
6304500114122001041
714113644630640105
oct1404013541066561
9227754063615287
1053053005000049
11159a472026292a
125b4a040046181
13237ab52737c22
14d15ac9d79905
1562006c978d84
hex30405d846d71

53053005000049 has 2 divisors, whose sum is σ = 53053005000050. Its totient is φ = 53053005000048.

The previous prime is 53053005000001. The next prime is 53053005000059. The reversal of 53053005000049 is 94000050035035.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52090761716449 + 962243283600 = 7217393^2 + 980940^2 .

It is a cyclic number.

It is not a de Polignac number, because 53053005000049 - 27 = 53053004999921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53053004999978 and 53053005000023.

It is not a weakly prime, because it can be changed into another prime (53053005000059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26526502500024 + 26526502500025.

It is an arithmetic number, because the mean of its divisors is an integer number (26526502500025).

Almost surely, 253053005000049 is an apocalyptic number.

It is an amenable number.

53053005000049 is a deficient number, since it is larger than the sum of its proper divisors (1).

53053005000049 is an equidigital number, since it uses as much as digits as its factorization.

53053005000049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40500, while the sum is 34.

The spelling of 53053005000049 in words is "fifty-three trillion, fifty-three billion, five million, forty-nine", and thus it is an aban number and an uban number.