Base | Representation |
---|---|
bin | 11000001000010001001101… |
… | …00001100101110000100000 |
3 | 20221212112212111002110022112 |
4 | 30010020212201211300200 |
5 | 23423321224103030100 |
6 | 304503423015054452 |
7 | 14114335632015212 |
oct | 1404104641456040 |
9 | 227775774073275 |
10 | 53060672314400 |
11 | 159a79a5261663 |
12 | 5b4b61b971428 |
13 | 237b7a5077a1a |
14 | d162163a25b2 |
15 | 62036ab5ab35 |
hex | 304226865c20 |
53060672314400 has 72 divisors (see below), whose sum is σ = 135166295303424. Its totient is φ = 20301474617600.
The previous prime is 53060672314399. The next prime is 53060672314439. The reversal of 53060672314400 is 441327606035.
It is a super-2 number, since 2×530606723144002 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1441847696 + ... + 1441884495.
It is an arithmetic number, because the mean of its divisors is an integer number (1877309656992).
Almost surely, 253060672314400 is an apocalyptic number.
53060672314400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53060672314400 is an abundant number, since it is smaller than the sum of its proper divisors (82105622989024).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53060672314400 is a wasteful number, since it uses less digits than its factorization.
53060672314400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2883732234 (or 2883732221 counting only the distinct ones).
The product of its (nonzero) digits is 362880, while the sum is 41.
The spelling of 53060672314400 in words is "fifty-three trillion, sixty billion, six hundred seventy-two million, three hundred fourteen thousand, four hundred".
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