Base | Representation |
---|---|
bin | 1001111000100110… |
… | …00010101100010001 |
3 | 111200211021210202002 |
4 | 10330103002230101 |
5 | 41331441421032 |
6 | 2234322403345 |
7 | 245334200516 |
oct | 47423025421 |
9 | 14624253662 |
10 | 5306592017 |
11 | 2283484141 |
12 | 1041200555 |
13 | 667526c9c |
14 | 384aad30d |
15 | 210d18862 |
hex | 13c4c2b11 |
5306592017 has 2 divisors, whose sum is σ = 5306592018. Its totient is φ = 5306592016.
The previous prime is 5306592013. The next prime is 5306592073. The reversal of 5306592017 is 7102956035.
It is a happy number.
5306592017 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2792171281 + 2514420736 = 52841^2 + 50144^2 .
It is a cyclic number.
It is not a de Polignac number, because 5306592017 - 22 = 5306592013 is a prime.
It is not a weakly prime, because it can be changed into another prime (5306592013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653296008 + 2653296009.
It is an arithmetic number, because the mean of its divisors is an integer number (2653296009).
Almost surely, 25306592017 is an apocalyptic number.
It is an amenable number.
5306592017 is a deficient number, since it is larger than the sum of its proper divisors (1).
5306592017 is an equidigital number, since it uses as much as digits as its factorization.
5306592017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56700, while the sum is 38.
The square root of 5306592017 is about 72846.3589824502. The cubic root of 5306592017 is about 1744.2359489538.
The spelling of 5306592017 in words is "five billion, three hundred six million, five hundred ninety-two thousand, seventeen".
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