Base | Representation |
---|---|
bin | 110001011101000101… |
… | …110011111100001011 |
3 | 12002001201200020012221 |
4 | 301131011303330023 |
5 | 1332222430141412 |
6 | 40221111314511 |
7 | 3556621361362 |
oct | 613505637413 |
9 | 162051606187 |
10 | 53101412107 |
11 | 2057a3a9957 |
12 | a35b67ba37 |
13 | 5013470713 |
14 | 27da5b47d9 |
15 | 15abcbbb07 |
hex | c5d173f0b |
53101412107 has 2 divisors, whose sum is σ = 53101412108. Its totient is φ = 53101412106.
The previous prime is 53101412101. The next prime is 53101412179. The reversal of 53101412107 is 70121410135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53101412107 - 23 = 53101412099 is a prime.
It is not a weakly prime, because it can be changed into another prime (53101412101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26550706053 + 26550706054.
It is an arithmetic number, because the mean of its divisors is an integer number (26550706054).
Almost surely, 253101412107 is an apocalyptic number.
53101412107 is a deficient number, since it is larger than the sum of its proper divisors (1).
53101412107 is an equidigital number, since it uses as much as digits as its factorization.
53101412107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
The spelling of 53101412107 in words is "fifty-three billion, one hundred one million, four hundred twelve thousand, one hundred seven".
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