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53101412101 is a prime number
BaseRepresentation
bin110001011101000101…
…110011111100000101
312002001201200020012201
4301131011303330011
51332222430141401
640221111314501
73556621361353
oct613505637405
9162051606181
1053101412101
112057a3a9951
12a35b67ba31
13501347070a
1427da5b47d3
1515abcbbb01
hexc5d173f05

53101412101 has 2 divisors, whose sum is σ = 53101412102. Its totient is φ = 53101412100.

The previous prime is 53101412099. The next prime is 53101412107. The reversal of 53101412101 is 10121410135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42778648900 + 10322763201 = 206830^2 + 101601^2 .

It is a cyclic number.

It is not a de Polignac number, because 53101412101 - 21 = 53101412099 is a prime.

It is a super-3 number, since 3×531014121013 (a number of 33 digits) contains 333 as substring.

Together with 53101412099, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53101412107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26550706050 + 26550706051.

It is an arithmetic number, because the mean of its divisors is an integer number (26550706051).

Almost surely, 253101412101 is an apocalyptic number.

It is an amenable number.

53101412101 is a deficient number, since it is larger than the sum of its proper divisors (1).

53101412101 is an equidigital number, since it uses as much as digits as its factorization.

53101412101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 53101412101 its reverse (10121410135), we get a palindrome (63222822236).

The spelling of 53101412101 in words is "fifty-three billion, one hundred one million, four hundred twelve thousand, one hundred one".