Base | Representation |
---|---|
bin | 111100010111101101010111… |
… | …1101000000000001011011110 |
3 | 2120122012102001110122021202120 |
4 | 1320233122233220000023132 |
5 | 1024100244340414322032 |
6 | 5121221035413403410 |
7 | 216565140360645426 |
oct | 17057325750001336 |
9 | 2518172043567676 |
10 | 531024113042142 |
11 | 144223075051215 |
12 | 4b684045039566 |
13 | 19a3c488926a35 |
14 | 951b9c04b3486 |
15 | 415d250d0d62c |
hex | 1e2f6afa002de |
531024113042142 has 128 divisors (see below), whose sum is σ = 1110968006400000. Its totient is φ = 169001998298112.
The previous prime is 531024113042083. The next prime is 531024113042149. The reversal of 531024113042142 is 241240311420135.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531024113042149) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8477500459 + ... + 8477563097.
It is an arithmetic number, because the mean of its divisors is an integer number (8679437550000).
Almost surely, 2531024113042142 is an apocalyptic number.
531024113042142 is an abundant number, since it is smaller than the sum of its proper divisors (579943893357858).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531024113042142 is a wasteful number, since it uses less digits than its factorization.
531024113042142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64178.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 531024113042142 its reverse (241240311420135), we get a palindrome (772264424462277).
The spelling of 531024113042142 in words is "five hundred thirty-one trillion, twenty-four billion, one hundred thirteen million, forty-two thousand, one hundred forty-two".
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