Base | Representation |
---|---|
bin | 11000001001100000110100… |
… | …00110011110111111000110 |
3 | 20222000122012012021110011220 |
4 | 30010300122012132333012 |
5 | 23430021242332231032 |
6 | 304535212120141210 |
7 | 14120411043405426 |
oct | 1404603206367706 |
9 | 228018165243156 |
10 | 53103413555142 |
11 | 15a14038604415 |
12 | 5b57969907806 |
13 | 2382827023212 |
14 | d1830ca5a486 |
15 | 62151d12212c |
hex | 304c1a19efc6 |
53103413555142 has 64 divisors (see below), whose sum is σ = 115431696753408. Its totient is φ = 16220451968000.
The previous prime is 53103413555141. The next prime is 53103413555161. The reversal of 53103413555142 is 24155531430135.
It is a junction number, because it is equal to n+sod(n) for n = 53103413555094 and 53103413555103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53103413555141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10877484 + ... + 14984207.
It is an arithmetic number, because the mean of its divisors is an integer number (1803620261772).
Almost surely, 253103413555142 is an apocalyptic number.
53103413555142 is an abundant number, since it is smaller than the sum of its proper divisors (62328283198266).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53103413555142 is a wasteful number, since it uses less digits than its factorization.
53103413555142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25862245.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 53103413555142 its reverse (24155531430135), we get a palindrome (77258944985277).
The spelling of 53103413555142 in words is "fifty-three trillion, one hundred three billion, four hundred thirteen million, five hundred fifty-five thousand, one hundred forty-two".
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