531101401301 has 2 divisors, whose sum is σ = 531101401302. Its totient is φ = 531101401300.

The previous prime is 531101401223. The next prime is 531101401379. The reversal of 531101401301 is 103104101135.

It is a balanced prime because it is at equal distance from previous prime (531101401223) and next prime (531101401379).

It can be written as a sum of positive squares in only one way, i.e., 423864800401 + 107236600900 = 651049^2 + 327470^2 .

It is a cyclic number.

It is not a de Polignac number, because 531101401301 - 2¹⁴ = 531101384917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531100401301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265550700650 + 265550700651.

It is an arithmetic number, because the mean of its divisors is an integer number (265550700651).

Almost surely, 2^531101401301 is an apocalyptic number.

It is an amenable number.

531101401301 is a deficient number, since it is larger than the sum of its proper divisors (1).

531101401301 is an equidigital number, since it uses as much as digits as its factorization.

531101401301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 531101401301 its reverse (103104101135), we get a palindrome (634205502436).

The spelling of 531101401301 in words is "five hundred thirty-one billion, one hundred one million, four hundred one thousand, three hundred one".