Base | Representation |
---|---|
bin | 11000001001101110111101… |
… | …11101010010110111001111 |
3 | 20222001100210200122001221021 |
4 | 30010313132331102313033 |
5 | 23430132322333200124 |
6 | 304542510044415011 |
7 | 14121100240500505 |
oct | 1404673675226717 |
9 | 228040720561837 |
10 | 53111011225039 |
11 | 15a17287265249 |
12 | 5b5932a247467 |
13 | 23834680ba291 |
14 | d1882db14675 |
15 | 6218151487e4 |
hex | 304ddef52dcf |
53111011225039 has 2 divisors, whose sum is σ = 53111011225040. Its totient is φ = 53111011225038.
The previous prime is 53111011224979. The next prime is 53111011225043. The reversal of 53111011225039 is 93052211011135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53111011225039 - 27 = 53111011224911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53111011224995 and 53111011225013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53111011220039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555505612519 + 26555505612520.
It is an arithmetic number, because the mean of its divisors is an integer number (26555505612520).
Almost surely, 253111011225039 is an apocalyptic number.
53111011225039 is a deficient number, since it is larger than the sum of its proper divisors (1).
53111011225039 is an equidigital number, since it uses as much as digits as its factorization.
53111011225039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 34.
The spelling of 53111011225039 in words is "fifty-three trillion, one hundred eleven billion, eleven million, two hundred twenty-five thousand, thirty-nine".
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