Base | Representation |
---|---|
bin | 110001011101101010… |
… | …110111010000101101 |
3 | 12002002101221200212002 |
4 | 301131222313100231 |
5 | 1332232422000122 |
6 | 40222055422045 |
7 | 3560100054065 |
oct | 613552672055 |
9 | 162071850762 |
10 | 53111125037 |
11 | 20584933373 |
12 | a362984925 |
13 | 5015491709 |
14 | 27db9c23a5 |
15 | 15aca89992 |
hex | c5dab742d |
53111125037 has 2 divisors, whose sum is σ = 53111125038. Its totient is φ = 53111125036.
The previous prime is 53111125031. The next prime is 53111125043. The reversal of 53111125037 is 73052111135.
It is a balanced prime because it is at equal distance from previous prime (53111125031) and next prime (53111125043).
It can be written as a sum of positive squares in only one way, i.e., 32163194281 + 20947930756 = 179341^2 + 144734^2 .
It is a cyclic number.
It is not a de Polignac number, because 53111125037 - 216 = 53111059501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53111125031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26555562518 + 26555562519.
It is an arithmetic number, because the mean of its divisors is an integer number (26555562519).
Almost surely, 253111125037 is an apocalyptic number.
It is an amenable number.
53111125037 is a deficient number, since it is larger than the sum of its proper divisors (1).
53111125037 is an equidigital number, since it uses as much as digits as its factorization.
53111125037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150, while the sum is 29.
The spelling of 53111125037 in words is "fifty-three billion, one hundred eleven million, one hundred twenty-five thousand, thirty-seven".
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