Base | Representation |
---|---|
bin | 100110101001001110011… |
… | …1010010001110110111101 |
3 | 200210202011111120220100021 |
4 | 1031102130322101312331 |
5 | 1144004330244213203 |
6 | 15143534231532141 |
7 | 1055502533654665 |
oct | 115223472216675 |
9 | 20722144526307 |
10 | 5311212101053 |
11 | 176852184a281 |
12 | 71942222a051 |
13 | 2c6acaa507a1 |
14 | 1450c7a0b1a5 |
15 | 932543b95bd |
hex | 4d49ce91dbd |
5311212101053 has 2 divisors, whose sum is σ = 5311212101054. Its totient is φ = 5311212101052.
The previous prime is 5311212101033. The next prime is 5311212101071. The reversal of 5311212101053 is 3501012121135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3915499052644 + 1395713048409 = 1978762^2 + 1181403^2 .
It is a cyclic number.
It is not a de Polignac number, because 5311212101053 - 25 = 5311212101021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5311212101033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655606050526 + 2655606050527.
It is an arithmetic number, because the mean of its divisors is an integer number (2655606050527).
Almost surely, 25311212101053 is an apocalyptic number.
It is an amenable number.
5311212101053 is a deficient number, since it is larger than the sum of its proper divisors (1).
5311212101053 is an equidigital number, since it uses as much as digits as its factorization.
5311212101053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 5311212101053 its reverse (3501012121135), we get a palindrome (8812224222188).
The spelling of 5311212101053 in words is "five trillion, three hundred eleven billion, two hundred twelve million, one hundred one thousand, fifty-three".
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