Base | Representation |
---|---|
bin | 100110101001010001001… |
… | …0101100111111001100100 |
3 | 200210202101211220221021210 |
4 | 1031102202111213321210 |
5 | 1144010022101432200 |
6 | 15143551243311420 |
7 | 1055505020631162 |
oct | 115224225477144 |
9 | 20722354827253 |
10 | 5311303155300 |
11 | 176856919071a |
12 | 71944881b570 |
13 | 2c6b1388153c |
14 | 1450d5b50232 |
15 | 9325c3a3650 |
hex | 4d4a2567e64 |
5311303155300 has 36 divisors (see below), whose sum is σ = 15367370463536. Its totient is φ = 1416347508000.
The previous prime is 5311303155241. The next prime is 5311303155371. The reversal of 5311303155300 is 35513031135.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8852171626 + ... + 8852172225.
Almost surely, 25311303155300 is an apocalyptic number.
5311303155300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5311303155300 is an abundant number, since it is smaller than the sum of its proper divisors (10056067308236).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5311303155300 is a wasteful number, since it uses less digits than its factorization.
5311303155300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17704343868 (or 17704343861 counting only the distinct ones).
The product of its (nonzero) digits is 10125, while the sum is 30.
Adding to 5311303155300 its reverse (35513031135), we get a palindrome (5346816186435).
The spelling of 5311303155300 in words is "five trillion, three hundred eleven billion, three hundred three million, one hundred fifty-five thousand, three hundred".
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