Base | Representation |
---|---|
bin | 100110101001011101101… |
… | …1000100000101110011110 |
3 | 200210210111010120200002221 |
4 | 1031102323120200232132 |
5 | 1144011402133432000 |
6 | 15144101053335554 |
7 | 1055521312312366 |
oct | 115227330405636 |
9 | 20723433520087 |
10 | 5311723342750 |
11 | 1768764394780 |
12 | 7195454975ba |
13 | 2c6b7c940676 |
14 | 14513588b9a6 |
15 | 9328420361a |
hex | 4d4bb620b9e |
5311723342750 has 128 divisors (see below), whose sum is σ = 11055824732160. Its totient is φ = 1894783968000.
The previous prime is 5311723342729. The next prime is 5311723342829. The reversal of 5311723342750 is 572433271135.
It is a junction number, because it is equal to n+sod(n) for n = 5311723342697 and 5311723342706.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 30997807 + ... + 31168693.
It is an arithmetic number, because the mean of its divisors is an integer number (86373630720).
Almost surely, 25311723342750 is an apocalyptic number.
5311723342750 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5311723342750 is an abundant number, since it is smaller than the sum of its proper divisors (5744101389410).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5311723342750 is a wasteful number, since it uses less digits than its factorization.
5311723342750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171131 (or 171121 counting only the distinct ones).
The product of its (nonzero) digits is 529200, while the sum is 43.
The spelling of 5311723342750 in words is "five trillion, three hundred eleven billion, seven hundred twenty-three million, three hundred forty-two thousand, seven hundred fifty".
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