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531240981941 is a prime number
BaseRepresentation
bin1111011101100000110…
…11100001010110110101
31212210020002122000210202
413232300123201112311
532200440142410231
61044014305530245
753244434561345
oct7566033412665
91783202560722
10531240981941
1119533075963a
1286b5b643985
133b132655ac7
141b9d83c8d25
15dc436905cb
hex7bb06e15b5

531240981941 has 2 divisors, whose sum is σ = 531240981942. Its totient is φ = 531240981940.

The previous prime is 531240981923. The next prime is 531240982009. The reversal of 531240981941 is 149189042135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 440525565841 + 90715416100 = 663721^2 + 301190^2 .

It is a cyclic number.

It is not a de Polignac number, because 531240981941 - 210 = 531240980917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531240987941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265620490970 + 265620490971.

It is an arithmetic number, because the mean of its divisors is an integer number (265620490971).

Almost surely, 2531240981941 is an apocalyptic number.

It is an amenable number.

531240981941 is a deficient number, since it is larger than the sum of its proper divisors (1).

531240981941 is an equidigital number, since it uses as much as digits as its factorization.

531240981941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 47.

The spelling of 531240981941 in words is "five hundred thirty-one billion, two hundred forty million, nine hundred eighty-one thousand, nine hundred forty-one".