Base | Representation |
---|---|
bin | 1111011101100001011… |
… | …00000111111110110010 |
3 | 1212210020101211011022210 |
4 | 13232300230013332302 |
5 | 32200442301200300 |
6 | 1044014543112550 |
7 | 53244516560025 |
oct | 7566054077662 |
9 | 1783211734283 |
10 | 531245334450 |
11 | 195333161756 |
12 | 86b60ba2756 |
13 | 3b13351ac5c |
14 | 1b9d8bdd1bc |
15 | dc43c50050 |
hex | 7bb0b07fb2 |
531245334450 has 48 divisors (see below), whose sum is σ = 1317743292960. Its totient is φ = 141638017920.
The previous prime is 531245334413. The next prime is 531245334479. The reversal of 531245334450 is 54433542135.
It is a junction number, because it is equal to n+sod(n) for n = 531245334399 and 531245334408.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 441397 + ... + 1121303.
It is an arithmetic number, because the mean of its divisors is an integer number (27452985270).
Almost surely, 2531245334450 is an apocalyptic number.
531245334450 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
531245334450 is an abundant number, since it is smaller than the sum of its proper divisors (786497958510).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531245334450 is a wasteful number, since it uses less digits than its factorization.
531245334450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 685131 (or 685126 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 39.
Adding to 531245334450 its reverse (54433542135), we get a palindrome (585678876585).
The spelling of 531245334450 in words is "five hundred thirty-one billion, two hundred forty-five million, three hundred thirty-four thousand, four hundred fifty".
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