Base | Representation |
---|---|
bin | 1100101010100… |
… | …1111111111101 |
3 | 10200222000221221 |
4 | 3022221333331 |
5 | 102100000432 |
6 | 5134353341 |
7 | 1213361503 |
oct | 312517775 |
9 | 120860857 |
10 | 53125117 |
11 | 27a95761 |
12 | 1595b851 |
13 | b0109a6 |
14 | 70ac673 |
15 | 49e5b97 |
hex | 32a9ffd |
53125117 has 2 divisors, whose sum is σ = 53125118. Its totient is φ = 53125116.
The previous prime is 53125099. The next prime is 53125139. The reversal of 53125117 is 71152135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40208281 + 12916836 = 6341^2 + 3594^2 .
It is a cyclic number.
It is not a de Polignac number, because 53125117 - 223 = 44736509 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53125091 and 53125100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53125157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26562558 + 26562559.
It is an arithmetic number, because the mean of its divisors is an integer number (26562559).
Almost surely, 253125117 is an apocalyptic number.
It is an amenable number.
53125117 is a deficient number, since it is larger than the sum of its proper divisors (1).
53125117 is an equidigital number, since it uses as much as digits as its factorization.
53125117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1050, while the sum is 25.
The square root of 53125117 is about 7288.6978946860. The cubic root of 53125117 is about 375.9239250232.
The spelling of 53125117 in words is "fifty-three million, one hundred twenty-five thousand, one hundred seventeen".
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