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53126563400 = 2352265632817
BaseRepresentation
bin110001011110100101…
…110000011001001000
312002010111000001022022
4301132211300121020
51332300400012100
640223410344012
73560345223641
oct613645603110
9162114001268
1053126563400
1120592618449
12a367b8b008
135018738741
1427dda806c8
1515ae0d8e85
hexc5e970648

53126563400 has 24 divisors (see below), whose sum is σ = 123519260370. Its totient is φ = 21250625280.

The previous prime is 53126563319. The next prime is 53126563421. The reversal of 53126563400 is 436562135.

It can be written as a sum of positive squares in 3 ways, for example, as 39174701476 + 13951861924 = 197926^2 + 118118^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 132816209 + ... + 132816608.

Almost surely, 253126563400 is an apocalyptic number.

53126563400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

53126563400 is an abundant number, since it is smaller than the sum of its proper divisors (70392696970).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53126563400 is a wasteful number, since it uses less digits than its factorization.

53126563400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265632833 (or 265632824 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 35.

The spelling of 53126563400 in words is "fifty-three billion, one hundred twenty-six million, five hundred sixty-three thousand, four hundred".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 200 265632817 531265634 1062531268 1328164085 2125062536 2656328170 5312656340 6640820425 10625312680 13281640850 26563281700 53126563400