Base | Representation |
---|---|
bin | 1111011101101001001… |
… | …00100100010001001111 |
3 | 1212210101221100222120102 |
4 | 13232310210210101033 |
5 | 32201110434241111 |
6 | 1044025231041315 |
7 | 53246240261246 |
oct | 7566444442117 |
9 | 1783357328512 |
10 | 531310462031 |
11 | 1953669a4aa8 |
12 | 86b7a97023b |
13 | 3b143b71a9b |
14 | 1ba0371395d |
15 | dc4981713b |
hex | 7bb492444f |
531310462031 has 2 divisors, whose sum is σ = 531310462032. Its totient is φ = 531310462030.
The previous prime is 531310462019. The next prime is 531310462057. The reversal of 531310462031 is 130264013135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 531310462031 - 210 = 531310461007 is a prime.
It is a super-2 number, since 2×5313104620312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 531310461985 and 531310462003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531310465031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265655231015 + 265655231016.
It is an arithmetic number, because the mean of its divisors is an integer number (265655231016).
Almost surely, 2531310462031 is an apocalyptic number.
531310462031 is a deficient number, since it is larger than the sum of its proper divisors (1).
531310462031 is an equidigital number, since it uses as much as digits as its factorization.
531310462031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 531310462031 its reverse (130264013135), we get a palindrome (661574475166).
The spelling of 531310462031 in words is "five hundred thirty-one billion, three hundred ten million, four hundred sixty-two thousand, thirty-one".
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