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53132119 is a prime number
BaseRepresentation
bin1100101010101…
…1101101010111
310200222101120021
43022223231113
5102100211434
65134450011
71213421065
oct312535527
9120871507
1053132119
1127a9aa47
1215963907
13b013c31
1470b1035
1549e7cb4
hex32abb57

53132119 has 2 divisors, whose sum is σ = 53132120. Its totient is φ = 53132118.

The previous prime is 53132087. The next prime is 53132143. The reversal of 53132119 is 91123135.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53132119 - 25 = 53132087 is a prime.

It is a super-2 number, since 2×531321192 = 5646044138860322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53132093 and 53132102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53132179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26566059 + 26566060.

It is an arithmetic number, because the mean of its divisors is an integer number (26566060).

Almost surely, 253132119 is an apocalyptic number.

53132119 is a deficient number, since it is larger than the sum of its proper divisors (1).

53132119 is an equidigital number, since it uses as much as digits as its factorization.

53132119 is an evil number, because the sum of its binary digits is even.

The product of its digits is 810, while the sum is 25.

The square root of 53132119 is about 7289.1782115682. The cubic root of 53132119 is about 375.9404401472.

The spelling of 53132119 in words is "fifty-three million, one hundred thirty-two thousand, one hundred nineteen".