Base | Representation |
---|---|
bin | 1111011101101010101… |
… | …01111101111011010101 |
3 | 1212210102211201220211121 |
4 | 13232311111331323111 |
5 | 32201122243142211 |
6 | 1044030412403541 |
7 | 53246455325632 |
oct | 7566525757325 |
9 | 1783384656747 |
10 | 531323412181 |
11 | 19537323a701 |
12 | 86b831765b1 |
13 | 3b1467573b3 |
14 | 1ba05325189 |
15 | dc4aa24271 |
hex | 7bb557ded5 |
531323412181 has 2 divisors, whose sum is σ = 531323412182. Its totient is φ = 531323412180.
The previous prime is 531323412163. The next prime is 531323412259. The reversal of 531323412181 is 181214323135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 422934311556 + 108389100625 = 650334^2 + 329225^2 .
It is a cyclic number.
It is not a de Polignac number, because 531323412181 - 235 = 496963673813 is a prime.
It is a super-2 number, since 2×5313234121812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531323412121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265661706090 + 265661706091.
It is an arithmetic number, because the mean of its divisors is an integer number (265661706091).
Almost surely, 2531323412181 is an apocalyptic number.
It is an amenable number.
531323412181 is a deficient number, since it is larger than the sum of its proper divisors (1).
531323412181 is an equidigital number, since it uses as much as digits as its factorization.
531323412181 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 34.
The spelling of 531323412181 in words is "five hundred thirty-one billion, three hundred twenty-three million, four hundred twelve thousand, one hundred eighty-one".
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