Base | Representation |
---|---|
bin | 11000001010011010011010… |
… | …00100000111010110011111 |
3 | 20222010121000001022102110222 |
4 | 30011031031010013112133 |
5 | 23431023103313440020 |
6 | 305001324210351555 |
7 | 14122554212310062 |
oct | 1405151504072637 |
9 | 228117001272428 |
10 | 53134333343135 |
11 | 15a26164a65810 |
12 | 5b6195888b5bb |
13 | 2385713b1c765 |
14 | d19a032d28d9 |
15 | 62222c885b25 |
hex | 30534d10759f |
53134333343135 has 64 divisors (see below), whose sum is σ = 75365245255680. Its totient is φ = 35548246984320.
The previous prime is 53134333343101. The next prime is 53134333343159.
53134333343135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53134333343135 - 28 = 53134333342879 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1978412 + ... + 10496798.
It is an arithmetic number, because the mean of its divisors is an integer number (1177581957120).
Almost surely, 253134333343135 is an apocalyptic number.
53134333343135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53134333343135 is a deficient number, since it is larger than the sum of its proper divisors (22230911912545).
53134333343135 is a wasteful number, since it uses less digits than its factorization.
53134333343135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8518596.
The product of its digits is 2624400, while the sum is 44.
It can be divided in two parts, 5313433 and 3343135, that added together give a palindrome (8656568).
The spelling of 53134333343135 in words is "fifty-three trillion, one hundred thirty-four billion, three hundred thirty-three million, three hundred forty-three thousand, one hundred thirty-five".
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