Base | Representation |
---|---|
bin | 110001011111011001… |
… | …000110000100101011 |
3 | 12002011102022210102012 |
4 | 301133121012010223 |
5 | 1332312321142142 |
6 | 40225011030135 |
7 | 3560600505344 |
oct | 613731060453 |
9 | 162142283365 |
10 | 53140021547 |
11 | 2059a17a788 |
12 | a37059b34b |
13 | 501b46b342 |
14 | 28017850cb |
15 | 15b0396882 |
hex | c5f64612b |
53140021547 has 2 divisors, whose sum is σ = 53140021548. Its totient is φ = 53140021546.
The previous prime is 53140021531. The next prime is 53140021577. The reversal of 53140021547 is 74512004135.
53140021547 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53140021547 - 24 = 53140021531 is a prime.
It is not a weakly prime, because it can be changed into another prime (53140021577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570010773 + 26570010774.
It is an arithmetic number, because the mean of its divisors is an integer number (26570010774).
Almost surely, 253140021547 is an apocalyptic number.
53140021547 is a deficient number, since it is larger than the sum of its proper divisors (1).
53140021547 is an equidigital number, since it uses as much as digits as its factorization.
53140021547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 32.
The spelling of 53140021547 in words is "fifty-three billion, one hundred forty million, twenty-one thousand, five hundred forty-seven".
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