Base | Representation |
---|---|
bin | 110001011111011001… |
… | …000110000100011011 |
3 | 12002011102022210101121 |
4 | 301133121012010123 |
5 | 1332312321142111 |
6 | 40225011030111 |
7 | 3560600505322 |
oct | 613731060433 |
9 | 162142283347 |
10 | 53140021531 |
11 | 2059a17a773 |
12 | a37059b337 |
13 | 501b46b32c |
14 | 28017850b9 |
15 | 15b0396871 |
hex | c5f64611b |
53140021531 has 2 divisors, whose sum is σ = 53140021532. Its totient is φ = 53140021530.
The previous prime is 53140021469. The next prime is 53140021547. The reversal of 53140021531 is 13512004135.
It is a happy number.
53140021531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53140021531 - 217 = 53139890459 is a prime.
It is a super-2 number, since 2×531400215312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53140021496 and 53140021505.
It is not a weakly prime, because it can be changed into another prime (53140022531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570010765 + 26570010766.
It is an arithmetic number, because the mean of its divisors is an integer number (26570010766).
Almost surely, 253140021531 is an apocalyptic number.
53140021531 is a deficient number, since it is larger than the sum of its proper divisors (1).
53140021531 is an equidigital number, since it uses as much as digits as its factorization.
53140021531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 53140021531 its reverse (13512004135), we get a palindrome (66652025666).
The spelling of 53140021531 in words is "fifty-three billion, one hundred forty million, twenty-one thousand, five hundred thirty-one".
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