53140045333 has 2 divisors, whose sum is σ = 53140045334. Its totient is φ = 53140045332.

The previous prime is 53140045261. The next prime is 53140045337. The reversal of 53140045333 is 33354004135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47883505329 + 5256540004 = 218823^2 + 72502^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53140045333 is a prime.

It is a super-4 number, since 4×53140045333⁴ (a number of 44 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53140045295 and 53140045304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53140045337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570022666 + 26570022667.

It is an arithmetic number, because the mean of its divisors is an integer number (26570022667).

Almost surely, 2^53140045333 is an apocalyptic number.

It is an amenable number.

53140045333 is a deficient number, since it is larger than the sum of its proper divisors (1).

53140045333 is an equidigital number, since it uses as much as digits as its factorization.

53140045333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 53140045333 its reverse (33354004135), we get a palindrome (86494049468).

The spelling of 53140045333 in words is "fifty-three billion, one hundred forty million, forty-five thousand, three hundred thirty-three".