Base | Representation |
---|---|
bin | 110001011111011001… |
… | …001011110111001101 |
3 | 12002011102100222221111 |
4 | 301133121023313031 |
5 | 1332312322422021 |
6 | 40225011332021 |
7 | 3560600634442 |
oct | 613731136715 |
9 | 162142328844 |
10 | 53140045261 |
11 | 2059a196586 |
12 | a3705b1011 |
13 | 501b479084 |
14 | 280178d9c9 |
15 | 15b039d8e1 |
hex | c5f64bdcd |
53140045261 has 2 divisors, whose sum is σ = 53140045262. Its totient is φ = 53140045260.
The previous prime is 53140045223. The next prime is 53140045333. The reversal of 53140045261 is 16254004135.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50449652100 + 2690393161 = 224610^2 + 51869^2 .
It is a cyclic number.
It is not a de Polignac number, because 53140045261 - 211 = 53140043213 is a prime.
It is a super-2 number, since 2×531400452612 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53140043261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570022630 + 26570022631.
It is an arithmetic number, because the mean of its divisors is an integer number (26570022631).
Almost surely, 253140045261 is an apocalyptic number.
It is an amenable number.
53140045261 is a deficient number, since it is larger than the sum of its proper divisors (1).
53140045261 is an equidigital number, since it uses as much as digits as its factorization.
53140045261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 53140045261 its reverse (16254004135), we get a palindrome (69394049396).
The spelling of 53140045261 in words is "fifty-three billion, one hundred forty million, forty-five thousand, two hundred sixty-one".
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