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53140274461 is a prime number
BaseRepresentation
bin110001011111011010…
…000011110100011101
312002011102210122100101
4301133122003310131
51332312402240321
640225020301101
73560602610611
oct613732036435
9162142718311
1053140274461
112059a3327aa
12a3706a1791
13501b5294b1
14280180d341
1515b03e6791
hexc5f683d1d

53140274461 has 2 divisors, whose sum is σ = 53140274462. Its totient is φ = 53140274460.

The previous prime is 53140274459. The next prime is 53140274503. The reversal of 53140274461 is 16447204135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47043007236 + 6097267225 = 216894^2 + 78085^2 .

It is a cyclic number.

It is not a de Polignac number, because 53140274461 - 21 = 53140274459 is a prime.

Together with 53140274459, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 53140274461.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53140274441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26570137230 + 26570137231.

It is an arithmetic number, because the mean of its divisors is an integer number (26570137231).

Almost surely, 253140274461 is an apocalyptic number.

It is an amenable number.

53140274461 is a deficient number, since it is larger than the sum of its proper divisors (1).

53140274461 is an equidigital number, since it uses as much as digits as its factorization.

53140274461 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80640, while the sum is 37.

Adding to 53140274461 its reverse (16447204135), we get a palindrome (69587478596).

The spelling of 53140274461 in words is "fifty-three billion, one hundred forty million, two hundred seventy-four thousand, four hundred sixty-one".