Base | Representation |
---|---|
bin | 110001011111100000… |
… | …101110010100110111 |
3 | 12002011120002101201222 |
4 | 301133200232110313 |
5 | 1332313324141211 |
6 | 40225121540555 |
7 | 3560623505042 |
oct | 613740562467 |
9 | 162146071658 |
10 | 53142021431 |
11 | 205a0316284 |
12 | a3711a475b |
13 | 501b9bb6c5 |
14 | 2801b45c59 |
15 | 15b063e1db |
hex | c5f82e537 |
53142021431 has 2 divisors, whose sum is σ = 53142021432. Its totient is φ = 53142021430.
The previous prime is 53142021421. The next prime is 53142021461. The reversal of 53142021431 is 13412024135.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53142021431 - 230 = 52068279607 is a prime.
It is a super-2 number, since 2×531420214312 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 53142021431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53142021421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26571010715 + 26571010716.
It is an arithmetic number, because the mean of its divisors is an integer number (26571010716).
Almost surely, 253142021431 is an apocalyptic number.
53142021431 is a deficient number, since it is larger than the sum of its proper divisors (1).
53142021431 is an equidigital number, since it uses as much as digits as its factorization.
53142021431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 53142021431 its reverse (13412024135), we get a palindrome (66554045566).
The spelling of 53142021431 in words is "fifty-three billion, one hundred forty-two million, twenty-one thousand, four hundred thirty-one".
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