Base | Representation |
---|---|
bin | 1111011101110111011… |
… | …10001101101001101101 |
3 | 1212210201022010001112012 |
4 | 13232323232031221231 |
5 | 32201332142300331 |
6 | 1044045154251005 |
7 | 53252225064065 |
oct | 7567356155155 |
9 | 1783638101465 |
10 | 531430431341 |
11 | 195418695797 |
12 | 86bb2b86a65 |
13 | 3b162987a44 |
14 | 1ba156223a5 |
15 | dc5511382b |
hex | 7bbbb8da6d |
531430431341 has 2 divisors, whose sum is σ = 531430431342. Its totient is φ = 531430431340.
The previous prime is 531430431331. The next prime is 531430431349. The reversal of 531430431341 is 143134034135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 266870394025 + 264560037316 = 516595^2 + 514354^2 .
It is a cyclic number.
It is not a de Polignac number, because 531430431341 - 222 = 531426237037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531430431298 and 531430431307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531430431349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265715215670 + 265715215671.
It is an arithmetic number, because the mean of its divisors is an integer number (265715215671).
Almost surely, 2531430431341 is an apocalyptic number.
It is an amenable number.
531430431341 is a deficient number, since it is larger than the sum of its proper divisors (1).
531430431341 is an equidigital number, since it uses as much as digits as its factorization.
531430431341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 531430431341 its reverse (143134034135), we get a palindrome (674564465476).
The spelling of 531430431341 in words is "five hundred thirty-one billion, four hundred thirty million, four hundred thirty-one thousand, three hundred forty-one".
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