Base | Representation |
---|---|
bin | 110001100000000000… |
… | …101111001001100011 |
3 | 12002012010212202101001 |
4 | 301200000233021203 |
5 | 1332323001212121 |
6 | 40230021452431 |
7 | 3561055026334 |
oct | 614000571143 |
9 | 162163782331 |
10 | 53150413411 |
11 | 205a50282a7 |
12 | a373b71117 |
13 | 5020669384 |
14 | 2802ccc28b |
15 | 15b124a991 |
hex | c6002f263 |
53150413411 has 2 divisors, whose sum is σ = 53150413412. Its totient is φ = 53150413410.
The previous prime is 53150413409. The next prime is 53150413423. The reversal of 53150413411 is 11431405135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53150413411 - 21 = 53150413409 is a prime.
Together with 53150413409, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 53150413411.
It is not a weakly prime, because it can be changed into another prime (53150413111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575206705 + 26575206706.
It is an arithmetic number, because the mean of its divisors is an integer number (26575206706).
Almost surely, 253150413411 is an apocalyptic number.
53150413411 is a deficient number, since it is larger than the sum of its proper divisors (1).
53150413411 is an equidigital number, since it uses as much as digits as its factorization.
53150413411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 53150413411 its reverse (11431405135), we get a palindrome (64581818546).
The spelling of 53150413411 in words is "fifty-three billion, one hundred fifty million, four hundred thirteen thousand, four hundred eleven".
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