Base | Representation |
---|---|
bin | 110001100000000000… |
… | …101111001001101111 |
3 | 12002012010212202101111 |
4 | 301200000233021233 |
5 | 1332323001212143 |
6 | 40230021452451 |
7 | 3561055026352 |
oct | 614000571157 |
9 | 162163782344 |
10 | 53150413423 |
11 | 205a5028308 |
12 | a373b71127 |
13 | 5020669393 |
14 | 2802ccc299 |
15 | 15b124a99d |
hex | c6002f26f |
53150413423 has 2 divisors, whose sum is σ = 53150413424. Its totient is φ = 53150413422.
The previous prime is 53150413411. The next prime is 53150413493. The reversal of 53150413423 is 32431405135.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53150413423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53150413493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575206711 + 26575206712.
It is an arithmetic number, because the mean of its divisors is an integer number (26575206712).
Almost surely, 253150413423 is an apocalyptic number.
53150413423 is a deficient number, since it is larger than the sum of its proper divisors (1).
53150413423 is an equidigital number, since it uses as much as digits as its factorization.
53150413423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 53150413423 its reverse (32431405135), we get a palindrome (85581818558).
The spelling of 53150413423 in words is "fifty-three billion, one hundred fifty million, four hundred thirteen thousand, four hundred twenty-three".
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