Base | Representation |
---|---|
bin | 11000001010111001101010… |
… | …01101100110000000010111 |
3 | 20222012012022110021112210001 |
4 | 30011130311031212000113 |
5 | 23431311434414401431 |
6 | 305013141221512131 |
7 | 14124020062360534 |
oct | 1405346515460027 |
9 | 228165273245701 |
10 | 53151113043991 |
11 | 15a32295737386 |
12 | 5b65060272647 |
13 | 238718929c231 |
14 | d1a755a27d8b |
15 | 6228b0a43e61 |
hex | 305735366017 |
53151113043991 has 2 divisors, whose sum is σ = 53151113043992. Its totient is φ = 53151113043990.
The previous prime is 53151113043983. The next prime is 53151113044019. The reversal of 53151113043991 is 19934031115135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53151113043991 - 23 = 53151113043983 is a prime.
It is a super-2 number, since 2×531511130439912 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53151113043971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575556521995 + 26575556521996.
It is an arithmetic number, because the mean of its divisors is an integer number (26575556521996).
Almost surely, 253151113043991 is an apocalyptic number.
53151113043991 is a deficient number, since it is larger than the sum of its proper divisors (1).
53151113043991 is an equidigital number, since it uses as much as digits as its factorization.
53151113043991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 218700, while the sum is 46.
The spelling of 53151113043991 in words is "fifty-three trillion, one hundred fifty-one billion, one hundred thirteen million, forty-three thousand, nine hundred ninety-one".
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