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53151113044019 is a prime number
BaseRepresentation
bin11000001010111001101010…
…01101100110000000110011
320222012012022110021112211002
430011130311031212000303
523431311434414402034
6305013141221512215
714124020062360604
oct1405346515460063
9228165273245732
1053151113044019
1115a32295737401
125b6506027266b
13238718929c253
14d1a755a27dab
156228b0a43e7e
hex305735366033

53151113044019 has 2 divisors, whose sum is σ = 53151113044020. Its totient is φ = 53151113044018.

The previous prime is 53151113043991. The next prime is 53151113044063. The reversal of 53151113044019 is 91044031115135.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53151113044019 is a prime.

It is a super-3 number, since 3×531511130440193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (53151113044619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575556522009 + 26575556522010.

It is an arithmetic number, because the mean of its divisors is an integer number (26575556522010).

Almost surely, 253151113044019 is an apocalyptic number.

53151113044019 is a deficient number, since it is larger than the sum of its proper divisors (1).

53151113044019 is an equidigital number, since it uses as much as digits as its factorization.

53151113044019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 38.

The spelling of 53151113044019 in words is "fifty-three trillion, one hundred fifty-one billion, one hundred thirteen million, forty-four thousand, nineteen".