Base | Representation |
---|---|
bin | 11000001010111001101010… |
… | …01101100110000000101011 |
3 | 20222012012022110021112210210 |
4 | 30011130311031212000223 |
5 | 23431311434414402021 |
6 | 305013141221512203 |
7 | 14124020062360563 |
oct | 1405346515460053 |
9 | 228165273245723 |
10 | 53151113044011 |
11 | 15a322957373a4 |
12 | 5b65060272663 |
13 | 238718929c248 |
14 | d1a755a27da3 |
15 | 6228b0a43e76 |
hex | 30573536602b |
53151113044011 has 8 divisors (see below), whose sum is σ = 70868211434640. Its totient is φ = 35434045008032.
The previous prime is 53151113043991. The next prime is 53151113044019. The reversal of 53151113044011 is 11044031115135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53151113044011 - 210 = 53151113042987 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53151113044011.
It is not an unprimeable number, because it can be changed into a prime (53151113044019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3128496 + ... + 10774493.
It is an arithmetic number, because the mean of its divisors is an integer number (8858526429330).
Almost surely, 253151113044011 is an apocalyptic number.
53151113044011 is a deficient number, since it is larger than the sum of its proper divisors (17717098390629).
53151113044011 is a wasteful number, since it uses less digits than its factorization.
53151113044011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15177325.
The product of its (nonzero) digits is 3600, while the sum is 30.
Adding to 53151113044011 its reverse (11044031115135), we get a palindrome (64195144159146).
The spelling of 53151113044011 in words is "fifty-three trillion, one hundred fifty-one billion, one hundred thirteen million, forty-four thousand, eleven".
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