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53151113044011 = 3127433313902989
BaseRepresentation
bin11000001010111001101010…
…01101100110000000101011
320222012012022110021112210210
430011130311031212000223
523431311434414402021
6305013141221512203
714124020062360563
oct1405346515460053
9228165273245723
1053151113044011
1115a322957373a4
125b65060272663
13238718929c248
14d1a755a27da3
156228b0a43e76
hex30573536602b

53151113044011 has 8 divisors (see below), whose sum is σ = 70868211434640. Its totient is φ = 35434045008032.

The previous prime is 53151113043991. The next prime is 53151113044019. The reversal of 53151113044011 is 11044031115135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53151113044011 - 210 = 53151113042987 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53151113044011.

It is not an unprimeable number, because it can be changed into a prime (53151113044019) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3128496 + ... + 10774493.

It is an arithmetic number, because the mean of its divisors is an integer number (8858526429330).

Almost surely, 253151113044011 is an apocalyptic number.

53151113044011 is a deficient number, since it is larger than the sum of its proper divisors (17717098390629).

53151113044011 is a wasteful number, since it uses less digits than its factorization.

53151113044011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15177325.

The product of its (nonzero) digits is 3600, while the sum is 30.

Adding to 53151113044011 its reverse (11044031115135), we get a palindrome (64195144159146).

The spelling of 53151113044011 in words is "fifty-three trillion, one hundred fifty-one billion, one hundred thirteen million, forty-four thousand, eleven".

Divisors: 1 3 1274333 3822999 13902989 41708967 17717037681337 53151113044011