Base | Representation |
---|---|
bin | 110001100001001110… |
… | …011001110000011111 |
3 | 12002020120012010111202 |
4 | 301201032121300133 |
5 | 1332343204214043 |
6 | 40232030110115 |
7 | 3561423053654 |
oct | 614116316037 |
9 | 162216163452 |
10 | 53170773023 |
11 | 20605573825 |
12 | a37a94b33b |
13 | 5024947394 |
14 | 28058abc2b |
15 | 15b2e1d1b8 |
hex | c61399c1f |
53170773023 has 2 divisors, whose sum is σ = 53170773024. Its totient is φ = 53170773022.
The previous prime is 53170773011. The next prime is 53170773031. The reversal of 53170773023 is 32037707135.
53170773023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53170773023 - 210 = 53170771999 is a prime.
It is a super-2 number, since 2×531707730232 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53170773053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26585386511 + 26585386512.
It is an arithmetic number, because the mean of its divisors is an integer number (26585386512).
Almost surely, 253170773023 is an apocalyptic number.
53170773023 is a deficient number, since it is larger than the sum of its proper divisors (1).
53170773023 is an equidigital number, since it uses as much as digits as its factorization.
53170773023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92610, while the sum is 38.
The spelling of 53170773023 in words is "fifty-three billion, one hundred seventy million, seven hundred seventy-three thousand, twenty-three".
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