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531940943 is a prime number
BaseRepresentation
bin11111101101001…
…100011001001111
31101001221101210102
4133231030121033
52042134102233
6124441201315
716116265142
oct3755143117
91331841712
10531940943
112532a3116
1212a19023b
1386289671
145090c059
1531a771e8
hex1fb4c64f

531940943 has 2 divisors, whose sum is σ = 531940944. Its totient is φ = 531940942.

The previous prime is 531940889. The next prime is 531940957. The reversal of 531940943 is 349049135.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 531940943 - 26 = 531940879 is a prime.

It is a super-2 number, since 2×5319409432 = 565922333679458498, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 531940897 and 531940906.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531943943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265970471 + 265970472.

It is an arithmetic number, because the mean of its divisors is an integer number (265970472).

Almost surely, 2531940943 is an apocalyptic number.

531940943 is a deficient number, since it is larger than the sum of its proper divisors (1).

531940943 is an equidigital number, since it uses as much as digits as its factorization.

531940943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58320, while the sum is 38.

The square root of 531940943 is about 23063.8449309737. The cubic root of 531940943 is about 810.2539177520.

The spelling of 531940943 in words is "five hundred thirty-one million, nine hundred forty thousand, nine hundred forty-three".