Base | Representation |
---|---|
bin | 100110101101011000011… |
… | …0000110101011110001101 |
3 | 200211121012100210102210121 |
4 | 1031122300300311132031 |
5 | 1144131114041320042 |
6 | 15152011502504541 |
7 | 1056236623152001 |
oct | 115326060653615 |
9 | 20747170712717 |
10 | 5320135104397 |
11 | 1771290630803 |
12 | 71b0b2595151 |
13 | 2c78c0582719 |
14 | 1456d2adc701 |
15 | 935c7937367 |
hex | 4d6b0c3578d |
5320135104397 has 2 divisors, whose sum is σ = 5320135104398. Its totient is φ = 5320135104396.
The previous prime is 5320135104343. The next prime is 5320135104419. The reversal of 5320135104397 is 7934015310235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5308996623876 + 11138480521 = 2304126^2 + 105539^2 .
It is a cyclic number.
It is not a de Polignac number, because 5320135104397 - 231 = 5317987620749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5320135104797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660067552198 + 2660067552199.
It is an arithmetic number, because the mean of its divisors is an integer number (2660067552199).
Almost surely, 25320135104397 is an apocalyptic number.
It is an amenable number.
5320135104397 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320135104397 is an equidigital number, since it uses as much as digits as its factorization.
5320135104397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 340200, while the sum is 43.
The spelling of 5320135104397 in words is "five trillion, three hundred twenty billion, one hundred thirty-five million, one hundred four thousand, three hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •