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5320135104397 is a prime number
BaseRepresentation
bin100110101101011000011…
…0000110101011110001101
3200211121012100210102210121
41031122300300311132031
51144131114041320042
615152011502504541
71056236623152001
oct115326060653615
920747170712717
105320135104397
111771290630803
1271b0b2595151
132c78c0582719
141456d2adc701
15935c7937367
hex4d6b0c3578d

5320135104397 has 2 divisors, whose sum is σ = 5320135104398. Its totient is φ = 5320135104396.

The previous prime is 5320135104343. The next prime is 5320135104419. The reversal of 5320135104397 is 7934015310235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5308996623876 + 11138480521 = 2304126^2 + 105539^2 .

It is a cyclic number.

It is not a de Polignac number, because 5320135104397 - 231 = 5317987620749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5320135104797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660067552198 + 2660067552199.

It is an arithmetic number, because the mean of its divisors is an integer number (2660067552199).

Almost surely, 25320135104397 is an apocalyptic number.

It is an amenable number.

5320135104397 is a deficient number, since it is larger than the sum of its proper divisors (1).

5320135104397 is an equidigital number, since it uses as much as digits as its factorization.

5320135104397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 340200, while the sum is 43.

The spelling of 5320135104397 in words is "five trillion, three hundred twenty billion, one hundred thirty-five million, one hundred four thousand, three hundred ninety-seven".